Good question. As I see it, yes, for every displacement x of the tyre in the vertical direction (I would call that y, but it's the same thing), the spring will be compressed a distance equal to
. This is valid for small displacements, because the angle with the horizontal will vary if you move the tyre too much in the vertical direction.
As for the forces, a vertical force Fx (also I would like to call it Fy, but...) will provide you with a force
.
The force Fx is composed of a force Fr, in the direction of the spring,
plus a force Fy that is pulling the lower arm.
Like this:
You can also think that the force Fx is making the suspension to rotate around the point where the spring is attached to the chassis, but this torque equal to "Fx * horizontal distance to chassis attachment point", that is trying to rotate the wheel in the counterclockwise direction is compensated by a torque equal to "Fy * vertical distance to chassis attachement point", which goes clockwise.
I'd say that an explanation to the stiffer suspension would be that you're changing movement in the vertical direction for a force that is trying to "rip" the wheel out of the car (or better, pulling the lower arm). The smaller is
, the larger the "ripping force".
... or so I think, but I know structures, not mechanical engineering, so all this is original "research".