2025/2026 Hybrid Powerunit speculation

[Tommy Cookers]

C5.4.5 At partial load, the fuel energy flow must not exceed the limit curve defined below:
EF (MJ/h) = 380 when the engine power is equal to or below -50kW
EF (MJ/h) = 9.78 x engine power (kW) + 869 when the engine power is above -50kW

Engine refers to full PU or ICE alone? Because I see no sense in the ICE producing minus 50kW.
I understand that the fuel at complete PU power = 0W (ICE vs MGUK for net zero) would be 869MJ/h, which amounts to 241,8kW of gross available power.
If the PU efficiency is nearing 50% (which we cannot know, at least right now), putting the ICE vs. MGUK with clutch disengaged and none torque request from the driver, it would be possible to harvest at 120kW. Not negligible!
Even then, the wording says "at partial load". What's the definition of load? Torque request ≠ load? Load on the ICE? Load in the full PU?
If the driver don't push on the throttle, could be accounted as another scenario not under " partial load", I suppose.

-50 kW or below is the ICE power (accelerator-off) for rpms above idle - ie so-called 'engine braking'
engine power means ICEngine power not Power Unit power

clutch-disengaged or clutch-engaged the energy sum is the same

[BassVirolla]

C5.4.5 At partial load, the fuel energy flow must not exceed the limit curve defined below:
EF (MJ/h) = 380 when the engine power is equal to or below -50kW
EF (MJ/h) = 9.78 x engine power (kW) + 869 when the engine power is above -50kW

Engine refers to full PU or ICE alone? Because I see no sense in the ICE producing minus 50kW.
I understand that the fuel at complete PU power = 0W (ICE vs MGUK for net zero) would be 869MJ/h, which amounts to 241,8kW of gross available power.
If the PU efficiency is nearing 50% (which we cannot know, at least right now), putting the ICE vs. MGUK with clutch disengaged and none torque request from the driver, it would be possible to harvest at 120kW. Not negligible!
Even then, the wording says "at partial load". What's the definition of load? Torque request ≠ load? Load on the ICE? Load in the full PU?
If the driver don't push on the throttle, could be accounted as another scenario not under " partial load", I suppose.

-50 kW or below is the ICE power (accelerator-off) for rpms above idle - ie so-called 'engine braking'
engine power means ICEngine power not Power Unit power

clutch-disengaged or clutch-engaged the energy sum is the same

Ok, I get it. This section of the rules is for overrun of the engine. I think this shuts the possibility to burn too much fuel for antilag effects.

Still not adressing the scenario I think about...

Nevertheless, I don't know (and I don't think) if the rules take "torque request" (as throttle position) as equal to "load".

That's the question, if it would be possible to load the engine only And exclusively against the MGUK while the driver requests no torque, but still not braking.