I think we need to know how the forces vary in different phases of 0-pi/2, pi/2-pi, pi-3pi/2, 3pi/2-2pi. Now if the displacement is determined through the cosine then the speed will be minus the sine. So the speed and displacement can have different signs.WilO wrote: ↑25 Feb 2018, 23:36Rustem,
While we wait for someone who really knows what they're talking about to respond, you might consider the content of the text you'd quoted, and whether or not it makes sense to you. Particularly the last bit about the direction of spring and damper forces in compression and rebound.
One of the fundamental parameters affecting 'grip' is the normal load on the tire. As such, minimizing the variation of this load about some mean value would be a good thing, if our primary concern were optimizing grip (and we had a driver that could make use of it).
So you might wonder why it would advantageous to have a wheel (tire and rim assembly) working against a high damper force in rebound.
I'm trying to figure out mathematical equations to find the wheel load at different damping levels when the road profile changes. Do I need to find a transmitting force in the suspension? What set of parameters do I need to know to predict the performance of the suspension? I want not so much to calculate a specific value, but to understand how the suspension works in a wide range of changing loads.
As Greg Locock has hinted there a several texts books that will help. There are also several other publcations that do the job & cost nothing (if cost is an issue). Alternatively, there are probably (I've not looked in detail) several computer "games" that might be made to work for you.Rustem 1988 wrote: ↑04 Mar 2018, 00:53I'm trying to figure out mathematical equations to find the wheel load at different damping levels when the road profile changes.
I think that if we have a damping force too high, the hysteresis curve will be wide, so the load change in different phases will also be great. Probably, we should try to reduce the change in load. We also need a compromise between the rate of variation of the load and the magnitude of the variation of the load.WilO wrote: ↑25 Feb 2018, 23:36Rustem,
While we wait for someone who really knows what they're talking about to respond, you might consider the content of the text you'd quoted, and whether or not it makes sense to you. Particularly the last bit about the direction of spring and damper forces in compression and rebound.
One of the fundamental parameters affecting 'grip' is the normal load on the tire. As such, minimizing the variation of this load about some mean value would be a good thing, if our primary concern were optimizing grip (and we had a driver that could make use of it).
So you might wonder why it would advantageous to have a wheel (tire and rim assembly) working against a high damper force in rebound.
I believe you have forgotten the inertia force acting on the wheel. If I simply rewrite your equation:Rustem 1988 wrote: ↑05 Mar 2018, 13:20...the load on the wheel W=Wst+ks(Xs-Xu)+Cs*(dXs/dt-dXu/dt)+kt(Xu-Xr)+Ct*(dXu/dt-dXr/dt)
Damping force and hysteresis are two different properties. The properties can be related in some damper designs, but it doesn't have to be the case. A damper force can be modeled quite accurately by a spring installed in series with a pure damper, where the stiffness may be different in compression and rebound.Rustem 1988 wrote: ↑05 Mar 2018, 14:25I think that if we have a damping force too high, the hysteresis curve will be wide.
Thank you for your comment. I meant a curve in the form elipsa for the damping force with spring force and the displacement or velocity.DaveW wrote: ↑05 Mar 2018, 17:42Damping force and hysteresis are two different properties. The properties can be related in some damper designs, but it doesn't have to be the case. A damper force can be modeled quite accurately by a spring installed in series with a pure damper, where the stiffness may be different in compression and rebound.Rustem 1988 wrote: ↑05 Mar 2018, 14:25I think that if we have a damping force too high, the hysteresis curve will be wide.
If we express the displacement of the shock absorber through cosine(x=x0*cos(w*t), where x0 -the amplitude of the displacement), then сompression can be during the phase from 0 to pi (or x0 to -x0). The velocity as derived from the displacement will be expressed through minus sine (v=-x0*w*sin(w*t)) and will be on the segment from 0 to pi negative, while the displacement on the segment 0-1/2 pi positive and negative on the segment 1/2 pi- pi. Since m*a = -k*x-c * v, where k*x - spring force, c*v-damping force, m * a is the force of inertia, the different signs at x and v spring force and damping force are also different signs. Therefore, the damping force and spring force will not always be in the same direction when the spring is compressed. (In this case, only on the segment 1/2 pi- pi.)Rustem 1988 wrote: ↑25 Feb 2018, 16:54I looked at the load for compression and rebound.
http://www.theoryinpracticeengineering. ... damper.pdf
Another contributing factor is the fact
that during compression the forces of the spring and damper are in the same direction
while during rebound the spring and damper forces act in opposite directions.
.... So not damper hysteresis. That could be confusing (it was to me...)Rustem 1988 wrote: ↑05 Mar 2018, 18:48Thank you for your comment. I meant a curve in the form elipsa for the damping force with spring force and the displacement or velocity.
Yes, not damper hysteresis.DaveW wrote: ↑05 Mar 2018, 22:48.... So not damper hysteresis.Rustem 1988 wrote: ↑05 Mar 2018, 18:48Thank you for your comment. I meant a curve in the form elipsa for the damping force with spring force and the displacement or velocity.