WhiteBlue wrote:
I have used only the smaller number of 1.5G for deceleration by drag. If you use the brakes the car have 5.5G. So in my scenario without brakes 1.5 G. So if you step off the throttle only the drag brakes with 27% of the total braking force
No you misunderstood the problem.
The will NEVER be 1,5G of drag for a car that would have a venturi worth of 11/1 ratio or even 8,5 L/D ratio.
First off, the figures quoted for F1 cars are 1g*, not 2G;
You logic is then fasle in many points:
-A car wouldn't have to be fitted with draggy wings; A simple venturi (like this is done on 599XX) would give even with let's say 7/1 @ 289 km/h (with 700kg of), 100kg of drag which would equal to 0.2G of deceleration.
-The example you've taken is irrealistic...you take a car at 300km/h...a road car would never do that; Even with a 3.5/1 ratio you would have 0.01g of deceleration...
-Even a F1 car with a wing of 3.5/1 ratio at 130km/h would have 0.3G of deceleration.
So now I say the drag breaking is 1.35 G. The drag force is 8035 N. The DF/drag is 2.5. That is miles away from your figure of 11 or even 3.5.
You completly get the problem wrong sorry... the venturi had 11 of ratio and the total car had 7.7/1 ratio..meaning that at @300km/H for 2000KG of DF you have
(20000/7.7)/620= 0,5g of deceleration...
There nothing complicated in those maths... a car that produces 2000KG of downforce and has a 7.7 L/D ratio produces 7.7 times less this amount, that is 2000/7.7 that is 258.7 kg.
Some help for you:
http://www.mulsannescorner.com/aerodata ... lmp03.html
Simple, practical calculations as you say...
*The 1G figures for F1 cars are because typical F1 wing has 3.5/1 L/D ratio.
for cars having 2000KG@ 300km/h than makes 2000/3.5= 571 kg: 5710/620= 0.93g's.