How ? Assume we are talking about 1.ab.xyz as the laptime. Assume that all 20 drivers are equally capable of driving strictly within 1.ab.000 to 1.ab.999, for each of their 50 laps.hollus wrote: ↑04 Sep 2024, 22:0320 drivers, about 50 laps... that's a 1000 chances for it to happen. And we only have 3 decimals.Oehrly wrote: ↑04 Sep 2024, 18:55About F1 driver consistency... what also seems to happen on average more than once per race (I haven't actually averaged it), is drivers setting the exact same lap time in two subsequent laps.
For example, this race:
Sainz 1:23.503 on Lap 26 and 27
Stroll 1:21.721 on Lap 21 and 22
That's just insane to me. I stumbled over this once when I just made the assumption that this rarely happens, because I thought the odds would be very low. Turns out, they aren't.
Given a particular xyz combination time for a lap :
The probability for ANY driver to get ANY two laps with exact same laptime is 20 x (1/1000) x 49/50 = 1.96%
The probability for ANY driver to get CONSECUTIVE laps with exact same laptime is 20 x (1/1000) x 1/49 = 0.041%
So those 3 decimals are plenty enough to make the chances for such a thing, really low, mathematically speaking.
Now, in the real world, track temp, tyre temp, air temp, grip level, fuel load, wind level/direction etc are likely to remain almost same for two consecutive laps, so the chances that the driver inputs remain almost exactly same, are not that low. Hence, because of all these 'physical' conditions helping, consecutive laps producing the same laptime is more likely than ANY two laps with same laptime.
The point I want to make is, such a thing being not that unlikely, is not because of 'we only have 3 decimals'.