There was an interesting discussion on a now long since forgotten thread about how much traction-force the F1 tyres can handle and at what downforce, ie what is the "coefficient of friction". I've given the issue some thought and came up with the following simplified model, where rolling friction is set to nil:
Dynamics tells us that Power (Watt) is Force (Newton) times Speed (Meters per second). If we imagine that the car has a continous wheel-power of 480 kW (650 Hp), through a magic-CVT, the traction-force will theoretically come down with speed going up according to this:
At 20 m/s (72 km/h), traction-force is 24 kN, at 30 m/s-16 kN, at 40 m/s-12 kN and so on to the point where traction-force balances the air-resistance, at some 300 km/h.
As the speed goes up, downfoce will increase of course, but at what speed does the wheel-spin stop and how much is the vertical contact-force between the rear wheels and the surface at that speed?