Explain clever people :P

Here are our CFD links and discussions about aerodynamics, suspension, driver safety and tyres. Please stick to F1 on this forum.
joselu43
joselu43
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Joined: 13 May 2006, 17:10

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Bernoulli does NOT apply close to the surface (boundary layer) because viscosity there is dominant. Across the boundary layer the pressure remains pretty much conatant while the velocity (relative to the surface) goes to zero at the very surface. The area rule aplies to transonic and supersonic flow.
Are you sure you mean "taper" and not "sweep". Taper refers to the fact that the cord of the wing at the tip is different from the one at the root (taper ratio). It is an important parameter, but not in terms of what we are taking about. Even most straight wings are tapered.

Jl
JL

joselu43
joselu43
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Joined: 13 May 2006, 17:10

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Also, I don't think that velocoties get anywhere near 500 - 600 mph in an F1 car.

Jl

PNSD
PNSD
3
Joined: 03 Apr 2006, 18:10

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Ciro Pabón
106
Joined: 11 May 2005, 00:31

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joselu43 wrote:Bernoulli does NOT apply close to the surface (boundary layer) because viscosity there is dominant... Also, I don't think that velocoties get anywhere near 500 - 600 mph in an F1 car.Jl
No, you are right, but the wind speed in some parts of the flow around the car could reach it. I was not referring to the boundary layer, but to the flow close to the body, at macroscopic distances, wherever it find restrictions in area or bow or shock waves. This is the reason subsonic airplanes have tapered wings.
Ciro

joselu43
joselu43
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Joined: 13 May 2006, 17:10

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Yes, outside the boundary layer the flow follows bernoulli, unless you have separation. The boundary layer is not microscopic, its thickness depends on geometry, on a curved surface like on an F1 car it may reach values of 1 inch, 2 - 3 cm. easily. As far as shock and bow waves, there is NO WAY they can appear unless the flow becomes sonic (Mach number = 1) first somewhere.


Jl