xpensive wrote:Your postings confuses me somewhat kilcoo.
Mixing of Apples and Pears are always annoying, what counts is of course the intake mass-flow and with your airflow-numbers, fuel represents 22% and should not be ignored. All mass is transformed to gas-form in the combustion process anyway.
What counts is the volume flow - volume flow/area defines speed.
As I have said a number of times now - the density of fuel is so high it is negligble. When it combusts with air, it adds negligble
volume to the flow.
It is not considered in calculations for sizing the throat or exit area of a turbofan engine core - I don't think it should be worried about here.
xpensive wrote:
It also seems that you are not totally comfortable with how a four-stroke engine operates. Your first number, 0.72 m^3/s should not be divided by four as in your second attempt, but with two, which gives a volumetric inlet flow of 0.36 m^3/s.
Correct - 4 strokes is 2 revolutions, therefore the earlier division by 4 is non-sensical.
xpensive wrote:
Other than that, air-density at 0C with five digits looks almost like copy'n paste to me, 1 kg/m^3 at 20C is a good enough approximation at this stage.
You want to include the effects of fuel, but are happy to throw away 20% of the air mass?
1.2256 is a bit much ok, 1.225 would do. Those numbers are not cut and paste, they are second nature, like 101325, 287 and 288. A bit nerdy, but hey, not as bad as knowing IP addresses!
xpensive wrote:
All in all 360 g/s of air, mixed with 50g/s of fuel results in a 12% mix, which sounds reasonable for a combustion engine, don't you agree?
Not really, sounds very very very fuel rich to me. However, this is an F1 engine, not your average road-car.
Then again, I'm used to turbofan combustor mixes, not reciprocating. A 12% mix will not get a turbo(jet)fan very far!