DaveKillens wrote:The vertical horns on the McLaren are immovable, they cannot be rotated to push left or right. And if subject to sidewinds from skidding or fast corners, the inside vertical would be blanketed by the airbox. So if the car was turning right, and sliding slightly, the left vertical horn would be pushed by the air, and try to roll the chassis to the right, unloading the outside tires. It would exert a slight push toward the direction of the turn, but since it is so high up, it would have a stronger push unloading the outside tires. Not desired.
I doubt the inside horn would be isolated to be honest.
I also disagree with the pushing of the air on the horn. The car will be rotating about the centreline on the rear axle, so the component of velocity on the horn will be from the inside to outside of the corner - hence the wing is pulling the car out. Unless the skid is greater than that component value I suppose.
We need numbers
If YR was the yaw rate in the corner, and X the distance from them horns to the rear axle with velocity V the component would be
([2*pi*X]/360)*[YR] + V*sin(YR) [approx]
but that does not include a sideslip angle.
I guess that the sideslip angle would simply subtract from yaw rate, so unless that is bigger, the horns will be pulling the car out from the corner. But the inside horn will be increasing the effective angle of attack of the rear wing.
But F1 cars have yaw rates of around 30 and even above 40 deg/sec, so you'd need a slip angle equal to that, and I think a typical optimal tyre slip angle is around 5 degrees.
http://www.datrontechnology.com/all/sit ... down&did=3