I wanted to calculate the speed a driver can loose if he suddenly move his wings up to 6° (in a right part of the track of course), with the new regulations which allows it.
Lets say that if the angle of the moveable wing is 0°, it doesn't induce more drag that the all car.
Lets say that the moveable surfacis is 0.25*0.25m at both sides of the nose. So with a 6° camber, the total "inducing drag surface" is S = 2*0.25*0.25*sin(6) = 130cm^2
Drag force can be written as : Fd = A*S*v*v
where A is a constant, and v the speed of the car.
I know that a F1 frontal surfacis is near 1.5 m^2.
Lets say the driver's speed is v1 = 300km/h. When the driver put the wing higher he looses speed.
The problem is the same if we say that the total drag is the same in both cases and if we are just looking for the speed of the car speed with wing angle = 6°.
v1*v1*(1.5)=v2*v2*(1.5 + 0.013) according to the drag formula
and then v2=298.7 km/h
So if the driver put up the wing to the maximum, he'll loose less than 2km/h, according to my calculation !
I know I've made too much hypothesis... especially italic part^^ but I don't know how to do in an other way.
If someone can give me the right answer, or correct myself... thanks to him !!
PS : sorry for my bad english...